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acceleration rate is a=g=9.8 m/s2
vt =v0+at = 0+ 9.8*3.41 = 33.418 m/s
vt2 - v02 = 2as
depth of the well is s= (33.4182 -0)/2/9.8 = 57 m
a = -9.8 m/s2
t = 3.41 s
vi = 0 m/s
d = ??
d = vi*t + 0.5*a*t2
d = (0 m/s)*(3.41 s)+ 0.5*(-9.8 m/s2)*(3.41 s)2
d = 0 m+ 0.5*(-9.8 m/s2)*(11.63 s2)
d = -57.0 m
(NOTE: the - sign indicates direction)